Metamath Proof Explorer


Theorem ssdif

Description: Difference law for subsets. (Contributed by NM, 28-May-1998)

Ref Expression
Assertion ssdif ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∖ 𝐶 ) ⊆ ( 𝐵 ∖ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 ssel ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) )
2 1 anim1d ⊢ ( 𝐴 ⊆ 𝐵 → ( ( 𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝐶 ) → ( 𝑥 ∈ 𝐵 ∧ ¬ 𝑥 ∈ 𝐶 ) ) )
3 eldif ⊢ ( 𝑥 ∈ ( 𝐴 ∖ 𝐶 ) ↔ ( 𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝐶 ) )
4 eldif ⊢ ( 𝑥 ∈ ( 𝐵 ∖ 𝐶 ) ↔ ( 𝑥 ∈ 𝐵 ∧ ¬ 𝑥 ∈ 𝐶 ) )
5 2 3 4 3imtr4g ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝑥 ∈ ( 𝐴 ∖ 𝐶 ) → 𝑥 ∈ ( 𝐵 ∖ 𝐶 ) ) )
6 5 ssrdv ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∖ 𝐶 ) ⊆ ( 𝐵 ∖ 𝐶 ) )