Metamath Proof Explorer


Theorem sseqtrdi

Description: A chained subclass and equality deduction. (Contributed by NM, 25-Apr-2004)

Ref Expression
Hypotheses sseqtrdi.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
sseqtrdi.2 ⊢ 𝐵 = 𝐶
Assertion sseqtrdi ( 𝜑 → 𝐴 ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 sseqtrdi.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
2 sseqtrdi.2 ⊢ 𝐵 = 𝐶
3 2 sseq2i ⊢ ( 𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ 𝐶 )
4 1 3 sylib ⊢ ( 𝜑 → 𝐴 ⊆ 𝐶 )