Metamath Proof Explorer


Theorem strfv2

Description: A variation on strfv to avoid asserting that S itself is a function, which involves sethood of all the ordered pair components of S . (Contributed by Mario Carneiro, 30-Apr-2015)

Ref Expression
Hypotheses strfv2.s ⊢ 𝑆 ∈ V
strfv2.f ⊢ Fun ◡ ◡ 𝑆
strfv2.e ⊢ 𝐸 = Slot ( 𝐸 ‘ ndx )
strfv2.n ⊢ ⟨ ( 𝐸 ‘ ndx ) , 𝐶 ⟩ ∈ 𝑆
Assertion strfv2 ( 𝐶 ∈ 𝑉 → 𝐶 = ( 𝐸 ‘ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 strfv2.s ⊢ 𝑆 ∈ V
2 strfv2.f ⊢ Fun ◡ ◡ 𝑆
3 strfv2.e ⊢ 𝐸 = Slot ( 𝐸 ‘ ndx )
4 strfv2.n ⊢ ⟨ ( 𝐸 ‘ ndx ) , 𝐶 ⟩ ∈ 𝑆
5 1 a1i ⊢ ( 𝐶 ∈ 𝑉 → 𝑆 ∈ V )
6 2 a1i ⊢ ( 𝐶 ∈ 𝑉 → Fun ◡ ◡ 𝑆 )
7 4 a1i ⊢ ( 𝐶 ∈ 𝑉 → ⟨ ( 𝐸 ‘ ndx ) , 𝐶 ⟩ ∈ 𝑆 )
8 id ⊢ ( 𝐶 ∈ 𝑉 → 𝐶 ∈ 𝑉 )
9 3 5 6 7 8 strfv2d ⊢ ( 𝐶 ∈ 𝑉 → 𝐶 = ( 𝐸 ‘ 𝑆 ) )