Metamath Proof Explorer


Theorem subrgcccrng1

Description: The one of a subring of the complex numbers. (Contributed by AV, 26-Oct-2026)

Ref Expression
Hypotheses subrgcccrng.r ⊢ 𝑅 = ( ℂfld ↾s 𝑆 )
subrgcccrng.s ⊢ 𝑆 ∈ ( SubRing ‘ ℂfld )
Assertion subrgcccrng1 1 = ( 1r ‘ 𝑅 )

Proof

Step Hyp Ref Expression
1 subrgcccrng.r ⊢ 𝑅 = ( ℂfld ↾s 𝑆 )
2 subrgcccrng.s ⊢ 𝑆 ∈ ( SubRing ‘ ℂfld )
3 cnfld1 ⊢ 1 = ( 1r ‘ ℂfld )
4 1 3 subrg1 ⊢ ( 𝑆 ∈ ( SubRing ‘ ℂfld ) → 1 = ( 1r ‘ 𝑅 ) )
5 2 4 ax-mp ⊢ 1 = ( 1r ‘ 𝑅 )