Metamath Proof Explorer


Theorem subrgcccrng1

Description: The one of a subring of the complex numbers. (Contributed by AV, 26-Oct-2026)

Ref Expression
Hypotheses subrgcccrng.r
|- R = ( CCfld |`s S )
subrgcccrng.s
|- S e. ( SubRing ` CCfld )
Assertion subrgcccrng1
|- 1 = ( 1r ` R )

Proof

Step Hyp Ref Expression
1 subrgcccrng.r
 |-  R = ( CCfld |`s S )
2 subrgcccrng.s
 |-  S e. ( SubRing ` CCfld )
3 cnfld1
 |-  1 = ( 1r ` CCfld )
4 1 3 subrg1
 |-  ( S e. ( SubRing ` CCfld ) -> 1 = ( 1r ` R ) )
5 2 4 ax-mp
 |-  1 = ( 1r ` R )