Metamath Proof Explorer


Theorem syldd

Description: Nested syllogism deduction. Deduction associated with syld . Double deduction associated with syl . (Contributed by NM, 12-Dec-2004) (Proof shortened by Wolf Lammen, 11-May-2013)

Ref Expression
Hypotheses syldd.1 ⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → 𝜃 ) ) )
syldd.2 ⊢ ( 𝜑 → ( 𝜓 → ( 𝜃 → 𝜏 ) ) )
Assertion syldd ( 𝜑 → ( 𝜓 → ( 𝜒 → 𝜏 ) ) )

Proof

Step Hyp Ref Expression
1 syldd.1 ⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → 𝜃 ) ) )
2 syldd.2 ⊢ ( 𝜑 → ( 𝜓 → ( 𝜃 → 𝜏 ) ) )
3 imim2 ⊢ ( ( 𝜃 → 𝜏 ) → ( ( 𝜒 → 𝜃 ) → ( 𝜒 → 𝜏 ) ) )
4 2 1 3 syl6c ⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → 𝜏 ) ) )