Metamath Proof Explorer


Theorem tposeqd

Description: Equality theorem for transposition. (Contributed by Mario Carneiro, 7-Jan-2017)

Ref Expression
Hypothesis tposeqd.1 ( 𝜑𝐹 = 𝐺 )
Assertion tposeqd ( 𝜑 → tpos 𝐹 = tpos 𝐺 )

Proof

Step Hyp Ref Expression
1 tposeqd.1 ( 𝜑𝐹 = 𝐺 )
2 tposeq ( 𝐹 = 𝐺 → tpos 𝐹 = tpos 𝐺 )
3 1 2 syl ( 𝜑 → tpos 𝐹 = tpos 𝐺 )