Metamath Proof Explorer


Theorem tposeq

Description: Equality theorem for transposition. (Contributed by Mario Carneiro, 10-Sep-2015)

Ref Expression
Assertion tposeq ( 𝐹 = 𝐺 → tpos 𝐹 = tpos 𝐺 )

Proof

Step Hyp Ref Expression
1 eqimss ( 𝐹 = 𝐺𝐹𝐺 )
2 tposss ( 𝐹𝐺 → tpos 𝐹 ⊆ tpos 𝐺 )
3 1 2 syl ( 𝐹 = 𝐺 → tpos 𝐹 ⊆ tpos 𝐺 )
4 eqimss2 ( 𝐹 = 𝐺𝐺𝐹 )
5 tposss ( 𝐺𝐹 → tpos 𝐺 ⊆ tpos 𝐹 )
6 4 5 syl ( 𝐹 = 𝐺 → tpos 𝐺 ⊆ tpos 𝐹 )
7 3 6 eqssd ( 𝐹 = 𝐺 → tpos 𝐹 = tpos 𝐺 )