Metamath Proof Explorer


Theorem tposf

Description: The domain and codomain of a transposition. (Contributed by NM, 10-Sep-2015)

Ref Expression
Assertion tposf ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐶 → tpos 𝐹 : ( 𝐵 × 𝐴 ) ⟶ 𝐶 )

Proof

Step Hyp Ref Expression
1 relxp ⊢ Rel ( 𝐴 × 𝐵 )
2 tposf2 ⊢ ( Rel ( 𝐴 × 𝐵 ) → ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐶 → tpos 𝐹 : ◡ ( 𝐴 × 𝐵 ) ⟶ 𝐶 ) )
3 1 2 ax-mp ⊢ ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐶 → tpos 𝐹 : ◡ ( 𝐴 × 𝐵 ) ⟶ 𝐶 )
4 cnvxp ⊢ ◡ ( 𝐴 × 𝐵 ) = ( 𝐵 × 𝐴 )
5 4 feq2i ⊢ ( tpos 𝐹 : ◡ ( 𝐴 × 𝐵 ) ⟶ 𝐶 ↔ tpos 𝐹 : ( 𝐵 × 𝐴 ) ⟶ 𝐶 )
6 3 5 sylib ⊢ ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐶 → tpos 𝐹 : ( 𝐵 × 𝐴 ) ⟶ 𝐶 )