Metamath Proof Explorer


Theorem undif

Description: Union of complementary parts into whole. (Contributed by NM, 22-Mar-1998)

Ref Expression
Assertion undif ( 𝐴 ⊆ 𝐵 ↔ ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) = 𝐵 )

Proof

Step Hyp Ref Expression
1 ssequn1 ⊢ ( 𝐴 ⊆ 𝐵 ↔ ( 𝐴 ∪ 𝐵 ) = 𝐵 )
2 undif2 ⊢ ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) = ( 𝐴 ∪ 𝐵 )
3 2 eqeq1i ⊢ ( ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) = 𝐵 ↔ ( 𝐴 ∪ 𝐵 ) = 𝐵 )
4 1 3 bitr4i ⊢ ( 𝐴 ⊆ 𝐵 ↔ ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) = 𝐵 )