Metamath Proof Explorer


Theorem up1st2nd2

Description: Rewrite the universal property predicate with separated parts. (Contributed by Zhi Wang, 23-Oct-2025)

Ref Expression
Hypothesis up1st2nd2.1 ( 𝜑𝑋 ∈ ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) )
Assertion up1st2nd2 ( 𝜑 → ( 1st𝑋 ) ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) ( 2nd𝑋 ) )

Proof

Step Hyp Ref Expression
1 up1st2nd2.1 ( 𝜑𝑋 ∈ ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) )
2 relup Rel ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 )
3 1st2ndbr ( ( Rel ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) ∧ 𝑋 ∈ ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) ) → ( 1st𝑋 ) ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) ( 2nd𝑋 ) )
4 2 1 3 sylancr ( 𝜑 → ( 1st𝑋 ) ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) ( 2nd𝑋 ) )