Metamath Proof Explorer


Theorem wfrlem2OLD

Description: Lemma for well-ordered recursion. An acceptable function is a function. Obsolete as of 18-Nov-2024. (New usage is discouraged.) (Proof modification is discouraged.) (Contributed by Scott Fenton, 21-Apr-2011)

Ref Expression
Hypothesis wfrlem1OLD.1 𝐵 = { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝐹 ‘ ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ) }
Assertion wfrlem2OLD ( 𝑔𝐵 → Fun 𝑔 )

Proof

Step Hyp Ref Expression
1 wfrlem1OLD.1 𝐵 = { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝐹 ‘ ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ) }
2 1 wfrlem1OLD 𝐵 = { 𝑔 ∣ ∃ 𝑧 ( 𝑔 Fn 𝑧 ∧ ( 𝑧𝐴 ∧ ∀ 𝑤𝑧 Pred ( 𝑅 , 𝐴 , 𝑤 ) ⊆ 𝑧 ) ∧ ∀ 𝑤𝑧 ( 𝑔𝑤 ) = ( 𝐹 ‘ ( 𝑔 ↾ Pred ( 𝑅 , 𝐴 , 𝑤 ) ) ) ) }
3 2 abeq2i ( 𝑔𝐵 ↔ ∃ 𝑧 ( 𝑔 Fn 𝑧 ∧ ( 𝑧𝐴 ∧ ∀ 𝑤𝑧 Pred ( 𝑅 , 𝐴 , 𝑤 ) ⊆ 𝑧 ) ∧ ∀ 𝑤𝑧 ( 𝑔𝑤 ) = ( 𝐹 ‘ ( 𝑔 ↾ Pred ( 𝑅 , 𝐴 , 𝑤 ) ) ) ) )
4 fnfun ( 𝑔 Fn 𝑧 → Fun 𝑔 )
5 4 3ad2ant1 ( ( 𝑔 Fn 𝑧 ∧ ( 𝑧𝐴 ∧ ∀ 𝑤𝑧 Pred ( 𝑅 , 𝐴 , 𝑤 ) ⊆ 𝑧 ) ∧ ∀ 𝑤𝑧 ( 𝑔𝑤 ) = ( 𝐹 ‘ ( 𝑔 ↾ Pred ( 𝑅 , 𝐴 , 𝑤 ) ) ) ) → Fun 𝑔 )
6 5 exlimiv ( ∃ 𝑧 ( 𝑔 Fn 𝑧 ∧ ( 𝑧𝐴 ∧ ∀ 𝑤𝑧 Pred ( 𝑅 , 𝐴 , 𝑤 ) ⊆ 𝑧 ) ∧ ∀ 𝑤𝑧 ( 𝑔𝑤 ) = ( 𝐹 ‘ ( 𝑔 ↾ Pred ( 𝑅 , 𝐴 , 𝑤 ) ) ) ) → Fun 𝑔 )
7 3 6 sylbi ( 𝑔𝐵 → Fun 𝑔 )