Metamath Proof Explorer


Theorem xpeq12

Description: Equality theorem for Cartesian product. (Contributed by FL, 31-Aug-2009)

Ref Expression
Assertion xpeq12 ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐷 ) )

Proof

Step Hyp Ref Expression
1 xpeq1 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐶 ) )
2 xpeq2 ⊢ ( 𝐶 = 𝐷 → ( 𝐵 × 𝐶 ) = ( 𝐵 × 𝐷 ) )
3 1 2 sylan9eq ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 × 𝐶 ) = ( 𝐵 × 𝐷 ) )