Metamath Proof Explorer


Theorem zabs0b

Description: An integer has an absolute value less than 1 iff it is 0. (Contributed by AV, 21-Nov-2025)

Ref Expression
Assertion zabs0b ( 𝑋 ∈ ℤ → ( ( abs ‘ 𝑋 ) < 1 ↔ 𝑋 = 0 ) )

Proof

Step Hyp Ref Expression
1 nn0abscl ( 𝑋 ∈ ℤ → ( abs ‘ 𝑋 ) ∈ ℕ0 )
2 nn0lt10b ( ( abs ‘ 𝑋 ) ∈ ℕ0 → ( ( abs ‘ 𝑋 ) < 1 ↔ ( abs ‘ 𝑋 ) = 0 ) )
3 1 2 syl ( 𝑋 ∈ ℤ → ( ( abs ‘ 𝑋 ) < 1 ↔ ( abs ‘ 𝑋 ) = 0 ) )
4 zcn ( 𝑋 ∈ ℤ → 𝑋 ∈ ℂ )
5 4 abs00ad ( 𝑋 ∈ ℤ → ( ( abs ‘ 𝑋 ) = 0 ↔ 𝑋 = 0 ) )
6 3 5 bitrd ( 𝑋 ∈ ℤ → ( ( abs ‘ 𝑋 ) < 1 ↔ 𝑋 = 0 ) )