Metamath Proof Explorer


Theorem znbas2

Description: The base set of Z/nZ is the same as the quotient ring it is based on. (Contributed by Mario Carneiro, 15-Jun-2015) (Revised by AV, 13-Jun-2019) (Revised by AV, 3-Nov-2024)

Ref Expression
Hypotheses znval2.s 𝑆 = ( RSpan ‘ ℤring )
znval2.u 𝑈 = ( ℤring /s ( ℤring ~QG ( 𝑆 ‘ { 𝑁 } ) ) )
znval2.y 𝑌 = ( ℤ/nℤ ‘ 𝑁 )
Assertion znbas2 ( 𝑁 ∈ ℕ0 → ( Base ‘ 𝑈 ) = ( Base ‘ 𝑌 ) )

Proof

Step Hyp Ref Expression
1 znval2.s 𝑆 = ( RSpan ‘ ℤring )
2 znval2.u 𝑈 = ( ℤring /s ( ℤring ~QG ( 𝑆 ‘ { 𝑁 } ) ) )
3 znval2.y 𝑌 = ( ℤ/nℤ ‘ 𝑁 )
4 baseid Base = Slot ( Base ‘ ndx )
5 plendxnbasendx ( le ‘ ndx ) ≠ ( Base ‘ ndx )
6 5 necomi ( Base ‘ ndx ) ≠ ( le ‘ ndx )
7 1 2 3 4 6 znbaslem ( 𝑁 ∈ ℕ0 → ( Base ‘ 𝑈 ) = ( Base ‘ 𝑌 ) )