Metamath Proof Explorer


Theorem 3eqtr3d

Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-1995) (Proof shortened by Andrew Salmon, 25-May-2011)

Ref Expression
Hypotheses 3eqtr3d.1
|- ( ph -> A = B )
3eqtr3d.2
|- ( ph -> A = C )
3eqtr3d.3
|- ( ph -> B = D )
Assertion 3eqtr3d
|- ( ph -> C = D )

Proof

Step Hyp Ref Expression
1 3eqtr3d.1
 |-  ( ph -> A = B )
2 3eqtr3d.2
 |-  ( ph -> A = C )
3 3eqtr3d.3
 |-  ( ph -> B = D )
4 1 2 eqtr3d
 |-  ( ph -> B = C )
5 4 3 eqtr3d
 |-  ( ph -> C = D )