Metamath Proof Explorer


Theorem 3eqtr3d

Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-1995) (Proof shortened by Andrew Salmon, 25-May-2011)

Ref Expression
Hypotheses 3eqtr3d.1 φ A = B
3eqtr3d.2 φ A = C
3eqtr3d.3 φ B = D
Assertion 3eqtr3d φ C = D

Proof

Step Hyp Ref Expression
1 3eqtr3d.1 φ A = B
2 3eqtr3d.2 φ A = C
3 3eqtr3d.3 φ B = D
4 1 2 eqtr3d φ B = C
5 4 3 eqtr3d φ C = D