Metamath Proof Explorer


Theorem 3p4e7

Description: 3 + 4 = 7. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 3p4e7
|- ( 3 + 4 ) = 7

Proof

Step Hyp Ref Expression
1 3cn
 |-  3 e. CC
2 2cn
 |-  2 e. CC
3 1 2 2 addassi
 |-  ( ( 3 + 2 ) + 2 ) = ( 3 + ( 2 + 2 ) )
4 3p2e5
 |-  ( 3 + 2 ) = 5
5 4 oveq1i
 |-  ( ( 3 + 2 ) + 2 ) = ( 5 + 2 )
6 5p2e7
 |-  ( 5 + 2 ) = 7
7 5 6 eqtri
 |-  ( ( 3 + 2 ) + 2 ) = 7
8 2p2e4
 |-  ( 2 + 2 ) = 4
9 8 oveq2i
 |-  ( 3 + ( 2 + 2 ) ) = ( 3 + 4 )
10 3 7 9 3eqtr3ri
 |-  ( 3 + 4 ) = 7