Metamath Proof Explorer


Theorem 3sstr3d

Description: Substitution of equality into both sides of a subclass relationship. (Contributed by NM, 1-Oct-2000)

Ref Expression
Hypotheses 3sstr3d.1
|- ( ph -> A C_ B )
3sstr3d.2
|- ( ph -> A = C )
3sstr3d.3
|- ( ph -> B = D )
Assertion 3sstr3d
|- ( ph -> C C_ D )

Proof

Step Hyp Ref Expression
1 3sstr3d.1
 |-  ( ph -> A C_ B )
2 3sstr3d.2
 |-  ( ph -> A = C )
3 3sstr3d.3
 |-  ( ph -> B = D )
4 2 3 sseq12d
 |-  ( ph -> ( A C_ B <-> C C_ D ) )
5 1 4 mpbid
 |-  ( ph -> C C_ D )