Metamath Proof Explorer
		
		
		
		Description:  Substitution of equality into both sides of a subclass relationship.
       (Contributed by NM, 1-Oct-2000)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | 3sstr3d.1 | ⊢ ( 𝜑  →  𝐴  ⊆  𝐵 ) | 
					
						|  |  | 3sstr3d.2 | ⊢ ( 𝜑  →  𝐴  =  𝐶 ) | 
					
						|  |  | 3sstr3d.3 | ⊢ ( 𝜑  →  𝐵  =  𝐷 ) | 
				
					|  | Assertion | 3sstr3d | ⊢  ( 𝜑  →  𝐶  ⊆  𝐷 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | 3sstr3d.1 | ⊢ ( 𝜑  →  𝐴  ⊆  𝐵 ) | 
						
							| 2 |  | 3sstr3d.2 | ⊢ ( 𝜑  →  𝐴  =  𝐶 ) | 
						
							| 3 |  | 3sstr3d.3 | ⊢ ( 𝜑  →  𝐵  =  𝐷 ) | 
						
							| 4 | 2 1 | eqsstrrd | ⊢ ( 𝜑  →  𝐶  ⊆  𝐵 ) | 
						
							| 5 | 4 3 | sseqtrd | ⊢ ( 𝜑  →  𝐶  ⊆  𝐷 ) |