Metamath Proof Explorer


Theorem 3sstr3g

Description: Substitution of equality into both sides of a subclass relationship. (Contributed by NM, 1-Oct-2000)

Ref Expression
Hypotheses 3sstr3g.1
|- ( ph -> A C_ B )
3sstr3g.2
|- A = C
3sstr3g.3
|- B = D
Assertion 3sstr3g
|- ( ph -> C C_ D )

Proof

Step Hyp Ref Expression
1 3sstr3g.1
 |-  ( ph -> A C_ B )
2 3sstr3g.2
 |-  A = C
3 3sstr3g.3
 |-  B = D
4 2 3 sseq12i
 |-  ( A C_ B <-> C C_ D )
5 1 4 sylib
 |-  ( ph -> C C_ D )