Metamath Proof Explorer
Description: Substitution of equality into both sides of a subclass relationship.
(Contributed by NM, 1-Oct-2000)
|
|
Ref |
Expression |
|
Hypotheses |
3sstr3g.1 |
|- ( ph -> A C_ B ) |
|
|
3sstr3g.2 |
|- A = C |
|
|
3sstr3g.3 |
|- B = D |
|
Assertion |
3sstr3g |
|- ( ph -> C C_ D ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3sstr3g.1 |
|- ( ph -> A C_ B ) |
2 |
|
3sstr3g.2 |
|- A = C |
3 |
|
3sstr3g.3 |
|- B = D |
4 |
2 3
|
sseq12i |
|- ( A C_ B <-> C C_ D ) |
5 |
1 4
|
sylib |
|- ( ph -> C C_ D ) |