Metamath Proof Explorer


Theorem bj-19.9htbi

Description: Strengthening 19.9ht by replacing its succedent with a biconditional ( 19.9t does have a biconditional succedent). This propagates. (Contributed by BJ, 20-Oct-2019)

Ref Expression
Assertion bj-19.9htbi
|- ( A. x ( ph -> A. x ph ) -> ( E. x ph <-> ph ) )

Proof

Step Hyp Ref Expression
1 19.9ht
 |-  ( A. x ( ph -> A. x ph ) -> ( E. x ph -> ph ) )
2 19.8a
 |-  ( ph -> E. x ph )
3 1 2 impbid1
 |-  ( A. x ( ph -> A. x ph ) -> ( E. x ph <-> ph ) )