Metamath Proof Explorer


Theorem bj-nnfbd

Description: If two formulas are equivalent for all x , then nonfreeness of x in one of them is equivalent to nonfreeness in the other, deduction form. See bj-nnfbi . (Contributed by BJ, 27-Aug-2023)

Ref Expression
Hypothesis bj-nnfbd.1
|- ( ph -> ( ps <-> ch ) )
Assertion bj-nnfbd
|- ( ph -> ( F// x ps <-> F// x ch ) )

Proof

Step Hyp Ref Expression
1 bj-nnfbd.1
 |-  ( ph -> ( ps <-> ch ) )
2 1 alrimiv
 |-  ( ph -> A. x ( ps <-> ch ) )
3 bj-nnfbi
 |-  ( ( ( ps <-> ch ) /\ A. x ( ps <-> ch ) ) -> ( F// x ps <-> F// x ch ) )
4 1 2 3 syl2anc
 |-  ( ph -> ( F// x ps <-> F// x ch ) )