Metamath Proof Explorer


Theorem cardeq0

Description: Only the empty set has cardinality zero. (Contributed by NM, 23-Apr-2004)

Ref Expression
Assertion cardeq0
|- ( A e. V -> ( ( card ` A ) = (/) <-> A = (/) ) )

Proof

Step Hyp Ref Expression
1 0ex
 |-  (/) e. _V
2 carden
 |-  ( ( A e. V /\ (/) e. _V ) -> ( ( card ` A ) = ( card ` (/) ) <-> A ~~ (/) ) )
3 1 2 mpan2
 |-  ( A e. V -> ( ( card ` A ) = ( card ` (/) ) <-> A ~~ (/) ) )
4 card0
 |-  ( card ` (/) ) = (/)
5 4 eqeq2i
 |-  ( ( card ` A ) = ( card ` (/) ) <-> ( card ` A ) = (/) )
6 en0
 |-  ( A ~~ (/) <-> A = (/) )
7 3 5 6 3bitr3g
 |-  ( A e. V -> ( ( card ` A ) = (/) <-> A = (/) ) )