Metamath Proof Explorer


Theorem cbvalvOLD

Description: Obsolete version of cbvalv as of 11-Sep-2023. (Contributed by NM, 5-Aug-1993) Remove dependency on ax-10 . (Revised by Wolf Lammen, 17-Jul-2021) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis cbvalv.1
|- ( x = y -> ( ph <-> ps ) )
Assertion cbvalvOLD
|- ( A. x ph <-> A. y ps )

Proof

Step Hyp Ref Expression
1 cbvalv.1
 |-  ( x = y -> ( ph <-> ps ) )
2 ax-5
 |-  ( ph -> A. y ph )
3 2 hbal
 |-  ( A. x ph -> A. y A. x ph )
4 1 spv
 |-  ( A. x ph -> ps )
5 3 4 alrimih
 |-  ( A. x ph -> A. y ps )
6 ax-5
 |-  ( ps -> A. x ps )
7 6 hbal
 |-  ( A. y ps -> A. x A. y ps )
8 1 equcoms
 |-  ( y = x -> ( ph <-> ps ) )
9 8 bicomd
 |-  ( y = x -> ( ps <-> ph ) )
10 9 spv
 |-  ( A. y ps -> ph )
11 7 10 alrimih
 |-  ( A. y ps -> A. x ph )
12 5 11 impbii
 |-  ( A. x ph <-> A. y ps )