Metamath Proof Explorer


Theorem chndin2

Description: Distribution of chain class constructor over alphabet intersection. (Contributed by Ender Ting, 24-Jul-2026)

Ref Expression
Assertion chndin2
|- ( R Chain ( B i^i C ) ) = ( ( R Chain B ) i^i ( R Chain C ) )

Proof

Step Hyp Ref Expression
1 chndrin
 |-  ( n e. ( R Chain ( B i^i C ) ) -> ( n e. ( R Chain B ) /\ n e. ( R Chain C ) ) )
2 chndin
 |-  ( ( n e. ( R Chain B ) /\ n e. ( R Chain C ) ) -> n e. ( R Chain ( B i^i C ) ) )
3 1 2 impbii
 |-  ( n e. ( R Chain ( B i^i C ) ) <-> ( n e. ( R Chain B ) /\ n e. ( R Chain C ) ) )
4 elin
 |-  ( n e. ( ( R Chain B ) i^i ( R Chain C ) ) <-> ( n e. ( R Chain B ) /\ n e. ( R Chain C ) ) )
5 3 4 bitr4i
 |-  ( n e. ( R Chain ( B i^i C ) ) <-> n e. ( ( R Chain B ) i^i ( R Chain C ) ) )
6 5 eqriv
 |-  ( R Chain ( B i^i C ) ) = ( ( R Chain B ) i^i ( R Chain C ) )