Metamath Proof Explorer


Theorem chnrin2

Description: Distribution of chain class constructor over relation intersection. (Contributed by Ender Ting, 24-Jul-2026)

Ref Expression
Assertion chnrin2
|- ( ( R i^i .< ) Chain B ) = ( ( R Chain B ) i^i ( .< Chain B ) )

Proof

Step Hyp Ref Expression
1 chnrrin
 |-  ( n e. ( ( R i^i .< ) Chain B ) -> ( n e. ( R Chain B ) /\ n e. ( .< Chain B ) ) )
2 chnrin
 |-  ( ( n e. ( R Chain B ) /\ n e. ( .< Chain B ) ) -> n e. ( ( R i^i .< ) Chain B ) )
3 1 2 impbii
 |-  ( n e. ( ( R i^i .< ) Chain B ) <-> ( n e. ( R Chain B ) /\ n e. ( .< Chain B ) ) )
4 elin
 |-  ( n e. ( ( R Chain B ) i^i ( .< Chain B ) ) <-> ( n e. ( R Chain B ) /\ n e. ( .< Chain B ) ) )
5 3 4 bitr4i
 |-  ( n e. ( ( R i^i .< ) Chain B ) <-> n e. ( ( R Chain B ) i^i ( .< Chain B ) ) )
6 5 eqriv
 |-  ( ( R i^i .< ) Chain B ) = ( ( R Chain B ) i^i ( .< Chain B ) )