Metamath Proof Explorer


Theorem cleq2lem

Description: Equality implies bijection. (Contributed by RP, 24-Jul-2020)

Ref Expression
Hypothesis cleq2lem.b
|- ( A = B -> ( ph <-> ps ) )
Assertion cleq2lem
|- ( A = B -> ( ( R C_ A /\ ph ) <-> ( R C_ B /\ ps ) ) )

Proof

Step Hyp Ref Expression
1 cleq2lem.b
 |-  ( A = B -> ( ph <-> ps ) )
2 sseq2
 |-  ( A = B -> ( R C_ A <-> R C_ B ) )
3 2 1 anbi12d
 |-  ( A = B -> ( ( R C_ A /\ ph ) <-> ( R C_ B /\ ps ) ) )