Metamath Proof Explorer

Theorem cnveqd

Description: Equality deduction for converse relation. (Contributed by NM, 6-Dec-2013)

Ref Expression
Hypothesis cnveqd.1 
|- ( ph -> A = B )
Assertion cnveqd 
|- ( ph -> `' A = `' B )

Proof

Step Hyp Ref Expression
1 cnveqd.1 
 |-  ( ph -> A = B )
2 cnveq 
 |-  ( A = B -> `' A = `' B )
3 1 2 syl 
 |-  ( ph -> `' A = `' B )