Metamath Proof Explorer


Theorem cnveqd

Description: Equality deduction for converse relation. (Contributed by NM, 6-Dec-2013)

Ref Expression
Hypothesis cnveqd.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion cnveqd ( 𝜑 → ◡ 𝐴 = ◡ 𝐵 )

Proof

Step Hyp Ref Expression
1 cnveqd.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 cnveq ⊢ ( 𝐴 = 𝐵 → ◡ 𝐴 = ◡ 𝐵 )
3 1 2 syl ⊢ ( 𝜑 → ◡ 𝐴 = ◡ 𝐵 )