Metamath Proof Explorer


Theorem ditgeq3sdv

Description: Equality theorem for the directed integral. Deduction form. (Contributed by GG, 1-Sep-2025)

Ref Expression
Hypothesis ditgeq3sdv.1
|- ( ph -> C = D )
Assertion ditgeq3sdv
|- ( ph -> S_ [ A -> B ] C _d x = S_ [ A -> B ] D _d x )

Proof

Step Hyp Ref Expression
1 ditgeq3sdv.1
 |-  ( ph -> C = D )
2 eqidd
 |-  ( ph -> A = A )
3 eqidd
 |-  ( ph -> B = B )
4 2 3 1 ditgeq123dv
 |-  ( ph -> S_ [ A -> B ] C _d x = S_ [ A -> B ] D _d x )