Metamath Proof Explorer
Description: Equality theorem for the directed integral. Deduction form.
(Contributed by GG, 1-Sep-2025)
|
|
Ref |
Expression |
|
Hypothesis |
ditgeq3sdv.1 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
|
Assertion |
ditgeq3sdv |
⊢ ( 𝜑 → ⨜ [ 𝐴 → 𝐵 ] 𝐶 d 𝑥 = ⨜ [ 𝐴 → 𝐵 ] 𝐷 d 𝑥 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ditgeq3sdv.1 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
2 |
|
eqidd |
⊢ ( 𝜑 → 𝐴 = 𝐴 ) |
3 |
|
eqidd |
⊢ ( 𝜑 → 𝐵 = 𝐵 ) |
4 |
2 3 1
|
ditgeq123dv |
⊢ ( 𝜑 → ⨜ [ 𝐴 → 𝐵 ] 𝐶 d 𝑥 = ⨜ [ 𝐴 → 𝐵 ] 𝐷 d 𝑥 ) |