Metamath Proof Explorer


Theorem ditgeq123dv

Description: Equality theorem for the directed integral. Deduction form. General version of ditgeq3sdv . (Contributed by GG, 1-Sep-2025)

Ref Expression
Hypotheses ditgeq123dv.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
ditgeq123dv.2 ⊢ ( 𝜑 → 𝐶 = 𝐷 )
ditgeq123dv.3 ⊢ ( 𝜑 → 𝐸 = 𝐹 )
Assertion ditgeq123dv ( 𝜑 → ⨜ [ 𝐴 → 𝐶 ] 𝐸 d 𝑥 = ⨜ [ 𝐵 → 𝐷 ] 𝐹 d 𝑥 )

Proof

Step Hyp Ref Expression
1 ditgeq123dv.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 ditgeq123dv.2 ⊢ ( 𝜑 → 𝐶 = 𝐷 )
3 ditgeq123dv.3 ⊢ ( 𝜑 → 𝐸 = 𝐹 )
4 1 2 breq12d ⊢ ( 𝜑 → ( 𝐴 ≤ 𝐶 ↔ 𝐵 ≤ 𝐷 ) )
5 1 2 oveq12d ⊢ ( 𝜑 → ( 𝐴 (,) 𝐶 ) = ( 𝐵 (,) 𝐷 ) )
6 5 3 itgeq12sdv ⊢ ( 𝜑 → ∫ ( 𝐴 (,) 𝐶 ) 𝐸 d 𝑥 = ∫ ( 𝐵 (,) 𝐷 ) 𝐹 d 𝑥 )
7 2 1 oveq12d ⊢ ( 𝜑 → ( 𝐶 (,) 𝐴 ) = ( 𝐷 (,) 𝐵 ) )
8 7 3 itgeq12sdv ⊢ ( 𝜑 → ∫ ( 𝐶 (,) 𝐴 ) 𝐸 d 𝑥 = ∫ ( 𝐷 (,) 𝐵 ) 𝐹 d 𝑥 )
9 8 negeqd ⊢ ( 𝜑 → - ∫ ( 𝐶 (,) 𝐴 ) 𝐸 d 𝑥 = - ∫ ( 𝐷 (,) 𝐵 ) 𝐹 d 𝑥 )
10 4 6 9 ifbieq12d ⊢ ( 𝜑 → if ( 𝐴 ≤ 𝐶 , ∫ ( 𝐴 (,) 𝐶 ) 𝐸 d 𝑥 , - ∫ ( 𝐶 (,) 𝐴 ) 𝐸 d 𝑥 ) = if ( 𝐵 ≤ 𝐷 , ∫ ( 𝐵 (,) 𝐷 ) 𝐹 d 𝑥 , - ∫ ( 𝐷 (,) 𝐵 ) 𝐹 d 𝑥 ) )
11 df-ditg ⊢ ⨜ [ 𝐴 → 𝐶 ] 𝐸 d 𝑥 = if ( 𝐴 ≤ 𝐶 , ∫ ( 𝐴 (,) 𝐶 ) 𝐸 d 𝑥 , - ∫ ( 𝐶 (,) 𝐴 ) 𝐸 d 𝑥 )
12 df-ditg ⊢ ⨜ [ 𝐵 → 𝐷 ] 𝐹 d 𝑥 = if ( 𝐵 ≤ 𝐷 , ∫ ( 𝐵 (,) 𝐷 ) 𝐹 d 𝑥 , - ∫ ( 𝐷 (,) 𝐵 ) 𝐹 d 𝑥 )
13 10 11 12 3eqtr4g ⊢ ( 𝜑 → ⨜ [ 𝐴 → 𝐶 ] 𝐸 d 𝑥 = ⨜ [ 𝐵 → 𝐷 ] 𝐹 d 𝑥 )