Theorem ee03an

Description: Conjunction form of ee03 . (Contributed by Alan Sare, 18-Jul-2011) (Proof modification is discouraged.) (New usage is discouraged.)

	Ref	Expression
Hypotheses	ee03an.1	|- ph
	ee03an.2	|- ( ps -> ( ch -> ( th -> ta ) ) )
	ee03an.3	|- ( ( ph /\ ta ) -> et )
Assertion	ee03an	|- ( ps -> ( ch -> ( th -> et ) ) )

Proof

Step	Hyp	Ref	Expression
1		ee03an.1	|- ph
2		ee03an.2	|- ( ps -> ( ch -> ( th -> ta ) ) )
3		ee03an.3	|- ( ( ph /\ ta ) -> et )
4	3	ex	|- ( ph -> ( ta -> et ) )
5	1 2 4	ee03	|- ( ps -> ( ch -> ( th -> et ) ) )