Metamath Proof Explorer


Theorem elpr

Description: A member of a pair of classes is one or the other of them, and conversely as soon as it is a set. Exercise 1 of TakeutiZaring p. 15. (Contributed by NM, 13-Sep-1995)

Ref Expression
Hypothesis elpr.1
|- A e. _V
Assertion elpr
|- ( A e. { B , C } <-> ( A = B \/ A = C ) )

Proof

Step Hyp Ref Expression
1 elpr.1
 |-  A e. _V
2 elprg
 |-  ( A e. _V -> ( A e. { B , C } <-> ( A = B \/ A = C ) ) )
3 1 2 ax-mp
 |-  ( A e. { B , C } <-> ( A = B \/ A = C ) )