Metamath Proof Explorer


Theorem elrn2

Description: Membership in a range. (Contributed by NM, 10-Jul-1994)

Ref Expression
Hypothesis elrn.1
|- A e. _V
Assertion elrn2
|- ( A e. ran B <-> E. x <. x , A >. e. B )

Proof

Step Hyp Ref Expression
1 elrn.1
 |-  A e. _V
2 opeq2
 |-  ( y = A -> <. x , y >. = <. x , A >. )
3 2 eleq1d
 |-  ( y = A -> ( <. x , y >. e. B <-> <. x , A >. e. B ) )
4 3 exbidv
 |-  ( y = A -> ( E. x <. x , y >. e. B <-> E. x <. x , A >. e. B ) )
5 dfrn3
 |-  ran B = { y | E. x <. x , y >. e. B }
6 1 4 5 elab2
 |-  ( A e. ran B <-> E. x <. x , A >. e. B )