Metamath Proof Explorer


Theorem eringring

Description: An endomorphism ring is a ring. TODO: fix comment. (Contributed by NM, 4-Aug-2013)

Ref Expression
Hypotheses ernggrp.h
|- H = ( LHyp ` K )
ernggrp.d
|- D = ( ( EDRing ` K ) ` W )
Assertion eringring
|- ( ( K e. HL /\ W e. H ) -> D e. Ring )

Proof

Step Hyp Ref Expression
1 ernggrp.h
 |-  H = ( LHyp ` K )
2 ernggrp.d
 |-  D = ( ( EDRing ` K ) ` W )
3 eqid
 |-  ( Base ` K ) = ( Base ` K )
4 eqid
 |-  ( ( LTrn ` K ) ` W ) = ( ( LTrn ` K ) ` W )
5 eqid
 |-  ( ( TEndo ` K ) ` W ) = ( ( TEndo ` K ) ` W )
6 eqid
 |-  ( a e. ( ( TEndo ` K ) ` W ) , b e. ( ( TEndo ` K ) ` W ) |-> ( f e. ( ( LTrn ` K ) ` W ) |-> ( ( a ` f ) o. ( b ` f ) ) ) ) = ( a e. ( ( TEndo ` K ) ` W ) , b e. ( ( TEndo ` K ) ` W ) |-> ( f e. ( ( LTrn ` K ) ` W ) |-> ( ( a ` f ) o. ( b ` f ) ) ) )
7 eqid
 |-  ( f e. ( ( LTrn ` K ) ` W ) |-> ( _I |` ( Base ` K ) ) ) = ( f e. ( ( LTrn ` K ) ` W ) |-> ( _I |` ( Base ` K ) ) )
8 eqid
 |-  ( a e. ( ( TEndo ` K ) ` W ) |-> ( f e. ( ( LTrn ` K ) ` W ) |-> `' ( a ` f ) ) ) = ( a e. ( ( TEndo ` K ) ` W ) |-> ( f e. ( ( LTrn ` K ) ` W ) |-> `' ( a ` f ) ) )
9 eqid
 |-  ( a e. ( ( TEndo ` K ) ` W ) , b e. ( ( TEndo ` K ) ` W ) |-> ( a o. b ) ) = ( a e. ( ( TEndo ` K ) ` W ) , b e. ( ( TEndo ` K ) ` W ) |-> ( a o. b ) )
10 1 2 3 4 5 6 7 8 9 erngdvlem3
 |-  ( ( K e. HL /\ W e. H ) -> D e. Ring )