Metamath Proof Explorer


Theorem exnelv

Description: For any set x , there is a set not contained in x . The proof is based on Russell's paradox. (Contributed by NM, 23-Aug-1993) Remove use of ax-12 and ax-13 . (Revised by BJ, 31-May-2019) Extract from nalset . (Revised by Matthew House, 12-Apr-2026)

Ref Expression
Assertion exnelv
|- E. y -. y e. x

Proof

Step Hyp Ref Expression
1 ax-sep
 |-  E. y A. z ( z e. y <-> ( z e. x /\ -. z e. z ) )
2 elequ1
 |-  ( z = y -> ( z e. x <-> y e. x ) )
3 elequ2
 |-  ( z = y -> ( z e. z <-> z e. y ) )
4 3 notbid
 |-  ( z = y -> ( -. z e. z <-> -. z e. y ) )
5 2 4 anbi12d
 |-  ( z = y -> ( ( z e. x /\ -. z e. z ) <-> ( y e. x /\ -. z e. y ) ) )
6 5 bibi2d
 |-  ( z = y -> ( ( z e. y <-> ( z e. x /\ -. z e. z ) ) <-> ( z e. y <-> ( y e. x /\ -. z e. y ) ) ) )
7 pclem6
 |-  ( ( z e. y <-> ( y e. x /\ -. z e. y ) ) -> -. y e. x )
8 6 7 biimtrdi
 |-  ( z = y -> ( ( z e. y <-> ( z e. x /\ -. z e. z ) ) -> -. y e. x ) )
9 8 spimvw
 |-  ( A. z ( z e. y <-> ( z e. x /\ -. z e. z ) ) -> -. y e. x )
10 1 9 eximii
 |-  E. y -. y e. x