Metamath Proof Explorer


Theorem imdistanri

Description: Distribution of implication with conjunction. (Contributed by NM, 8-Jan-2002)

Ref Expression
Hypothesis imdistanri.1
|- ( ph -> ( ps -> ch ) )
Assertion imdistanri
|- ( ( ps /\ ph ) -> ( ch /\ ph ) )

Proof

Step Hyp Ref Expression
1 imdistanri.1
 |-  ( ph -> ( ps -> ch ) )
2 1 com12
 |-  ( ps -> ( ph -> ch ) )
3 2 impac
 |-  ( ( ps /\ ph ) -> ( ch /\ ph ) )