Metamath Proof Explorer


Theorem imdistanri

Description: Distribution of implication with conjunction. (Contributed by NM, 8-Jan-2002)

Ref Expression
Hypothesis imdistanri.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
Assertion imdistanri ( ( 𝜓 ∧ 𝜑 ) → ( 𝜒 ∧ 𝜑 ) )

Proof

Step Hyp Ref Expression
1 imdistanri.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
2 1 com12 ⊢ ( 𝜓 → ( 𝜑 → 𝜒 ) )
3 2 impac ⊢ ( ( 𝜓 ∧ 𝜑 ) → ( 𝜒 ∧ 𝜑 ) )