Metamath Proof Explorer


Theorem inteqi

Description: Equality inference for class intersection. (Contributed by NM, 2-Sep-2003)

Ref Expression
Hypothesis inteqi.1
|- A = B
Assertion inteqi
|- |^| A = |^| B

Proof

Step Hyp Ref Expression
1 inteqi.1
 |-  A = B
2 inteq
 |-  ( A = B -> |^| A = |^| B )
3 1 2 ax-mp
 |-  |^| A = |^| B