Metamath Proof Explorer


Theorem ndmaovrcl

Description: Reverse closure law, in contrast to ndmovrcl where it is required that the operation's domain doesn't contain the empty set ( -. (/) e. S ), no additional asumption is required. (Contributed by Alexander van der Vekens, 26-May-2017)

Ref Expression
Hypothesis ndmaov.1
|- dom F = ( S X. S )
Assertion ndmaovrcl
|- ( (( A F B )) e. S -> ( A e. S /\ B e. S ) )

Proof

Step Hyp Ref Expression
1 ndmaov.1
 |-  dom F = ( S X. S )
2 aovvdm
 |-  ( (( A F B )) e. S -> <. A , B >. e. dom F )
3 opelxp
 |-  ( <. A , B >. e. ( S X. S ) <-> ( A e. S /\ B e. S ) )
4 3 biimpi
 |-  ( <. A , B >. e. ( S X. S ) -> ( A e. S /\ B e. S ) )
5 4 1 eleq2s
 |-  ( <. A , B >. e. dom F -> ( A e. S /\ B e. S ) )
6 2 5 syl
 |-  ( (( A F B )) e. S -> ( A e. S /\ B e. S ) )