Metamath Proof Explorer


Theorem nfcvb

Description: The "distinctor" expression -. A. x x = y , stating that x and y are not the same variable, can be written in terms of F/ in the obvious way. This theorem is not true in a one-element domain, because then F/_ x y and A. x x = y will both be true. (Contributed by Mario Carneiro, 8-Oct-2016) Usage of this theorem is discouraged because it depends on ax-13 . (New usage is discouraged.)

Ref Expression
Assertion nfcvb
|- ( F/_ x y <-> -. A. x x = y )

Proof

Step Hyp Ref Expression
1 nfnid
 |-  -. F/_ y y
2 eqidd
 |-  ( A. x x = y -> y = y )
3 2 drnfc1
 |-  ( A. x x = y -> ( F/_ x y <-> F/_ y y ) )
4 1 3 mtbiri
 |-  ( A. x x = y -> -. F/_ x y )
5 4 con2i
 |-  ( F/_ x y -> -. A. x x = y )
6 nfcvf
 |-  ( -. A. x x = y -> F/_ x y )
7 5 6 impbii
 |-  ( F/_ x y <-> -. A. x x = y )