Metamath Proof Explorer


Theorem nfcvb

Description: The "distinctor" expression -. A. x x = y , stating that x and y are not the same variable, can be written in terms of F/ in the obvious way. This theorem is not true in a one-element domain, because then F/_ x y and A. x x = y will both be true. (Contributed by Mario Carneiro, 8-Oct-2016) Usage of this theorem is discouraged because it depends on ax-13 . (New usage is discouraged.)

Ref Expression
Assertion nfcvb _ x y ¬ x x = y

Proof

Step Hyp Ref Expression
1 nfnid ¬ _ y y
2 eqidd x x = y y = y
3 2 drnfc1 x x = y _ x y _ y y
4 1 3 mtbiri x x = y ¬ _ x y
5 4 con2i _ x y ¬ x x = y
6 nfcvf ¬ x x = y _ x y
7 5 6 impbii _ x y ¬ x x = y