Metamath Proof Explorer


Theorem orcomdd

Description: Commutativity of logic disjunction, in double deduction form. Should not be moved to main, see PR #3034 in Github. Use orcomd instead. (Contributed by Giovanni Mascellani, 19-Mar-2018) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Hypothesis orcomdd.1
|- ( ph -> ( ps -> ( ch \/ th ) ) )
Assertion orcomdd
|- ( ph -> ( ps -> ( th \/ ch ) ) )

Proof

Step Hyp Ref Expression
1 orcomdd.1
 |-  ( ph -> ( ps -> ( ch \/ th ) ) )
2 pm1.4
 |-  ( ( ch \/ th ) -> ( th \/ ch ) )
3 1 2 syl6
 |-  ( ph -> ( ps -> ( th \/ ch ) ) )