Theorem orcomd

Description: Commutation of disjuncts in consequent. (Contributed by NM, 2-Dec-2010)

	Ref	Expression
Hypothesis	orcomd.1	|- ( ph -> ( ps \/ ch ) )
Assertion	orcomd	|- ( ph -> ( ch \/ ps ) )

Proof

Step	Hyp	Ref	Expression
1		orcomd.1	|- ( ph -> ( ps \/ ch ) )
2		orcom	|- ( ( ps \/ ch ) <-> ( ch \/ ps ) )
3	1 2	sylib	|- ( ph -> ( ch \/ ps ) )