Metamath Proof Explorer


Theorem orcomd

Description: Commutation of disjuncts in consequent. (Contributed by NM, 2-Dec-2010)

Ref Expression
Hypothesis orcomd.1 ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ) )
Assertion orcomd ( 𝜑 → ( 𝜒 ∨ 𝜓 ) )

Proof

Step Hyp Ref Expression
1 orcomd.1 ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ) )
2 orcom ⊢ ( ( 𝜓 ∨ 𝜒 ) ↔ ( 𝜒 ∨ 𝜓 ) )
3 1 2 sylib ⊢ ( 𝜑 → ( 𝜒 ∨ 𝜓 ) )