Metamath Proof Explorer


Theorem orim12d

Description: Disjoin antecedents and consequents in a deduction. See orim12dALT for a proof which does not depend on df-an . (Contributed by NM, 10-May-1994)

Ref Expression
Hypotheses orim12d.1
|- ( ph -> ( ps -> ch ) )
orim12d.2
|- ( ph -> ( th -> ta ) )
Assertion orim12d
|- ( ph -> ( ( ps \/ th ) -> ( ch \/ ta ) ) )

Proof

Step Hyp Ref Expression
1 orim12d.1
 |-  ( ph -> ( ps -> ch ) )
2 orim12d.2
 |-  ( ph -> ( th -> ta ) )
3 pm3.48
 |-  ( ( ( ps -> ch ) /\ ( th -> ta ) ) -> ( ( ps \/ th ) -> ( ch \/ ta ) ) )
4 1 2 3 syl2anc
 |-  ( ph -> ( ( ps \/ th ) -> ( ch \/ ta ) ) )