Metamath Proof Explorer


Theorem rspceeqv

Description: Restricted existential specialization in an equality, using implicit substitution. (Contributed by BJ, 2-Sep-2022)

Ref Expression
Hypothesis rspceeqv.1
|- ( x = A -> C = D )
Assertion rspceeqv
|- ( ( A e. B /\ E = D ) -> E. x e. B E = C )

Proof

Step Hyp Ref Expression
1 rspceeqv.1
 |-  ( x = A -> C = D )
2 1 eqeq2d
 |-  ( x = A -> ( E = C <-> E = D ) )
3 2 rspcev
 |-  ( ( A e. B /\ E = D ) -> E. x e. B E = C )