Metamath Proof Explorer


Theorem rspceeqv

Description: Restricted existential specialization in an equality, using implicit substitution. (Contributed by BJ, 2-Sep-2022)

Ref Expression
Hypothesis rspceeqv.1 ( 𝑥 = 𝐴𝐶 = 𝐷 )
Assertion rspceeqv ( ( 𝐴𝐵𝐸 = 𝐷 ) → ∃ 𝑥𝐵 𝐸 = 𝐶 )

Proof

Step Hyp Ref Expression
1 rspceeqv.1 ( 𝑥 = 𝐴𝐶 = 𝐷 )
2 1 eqeq2d ( 𝑥 = 𝐴 → ( 𝐸 = 𝐶𝐸 = 𝐷 ) )
3 2 rspcev ( ( 𝐴𝐵𝐸 = 𝐷 ) → ∃ 𝑥𝐵 𝐸 = 𝐶 )