Metamath Proof Explorer


Theorem rspceeqv

Description: Restricted existential specialization in an equality, using implicit substitution. (Contributed by BJ, 2-Sep-2022)

Ref Expression
Hypothesis rspceeqv.1 ⊢ ( 𝑥 = 𝐴 → 𝐶 = 𝐷 )
Assertion rspceeqv ( ( 𝐴 ∈ 𝐵 ∧ 𝐸 = 𝐷 ) → ∃ 𝑥 ∈ 𝐵 𝐸 = 𝐶 )

Proof

Step Hyp Ref Expression
1 rspceeqv.1 ⊢ ( 𝑥 = 𝐴 → 𝐶 = 𝐷 )
2 1 eqeq2d ⊢ ( 𝑥 = 𝐴 → ( 𝐸 = 𝐶 ↔ 𝐸 = 𝐷 ) )
3 2 rspcev ⊢ ( ( 𝐴 ∈ 𝐵 ∧ 𝐸 = 𝐷 ) → ∃ 𝑥 ∈ 𝐵 𝐸 = 𝐶 )